Gauss seidel

A=input("Enter the matrix A : ")
b=input("Enter the matrix b : ")
c=input("initial approx")
[r,m]=size(A)
l=1

while l~=10
    for i=1:r
        z=0
        for j=1:m
            if i~=j
                z=z+A(i,j)*c(j)
            end
        end
    c(i)=(b(i)-z)/A(i,i)
end
l=l+1
end
disp(c)

False position method or Regular falsi method

False position method or Regular falsi method



Code is Here

//false position method or regular falsi method
clear;clc;close
deff('y=f(x)','y=x^2.2-69');
printf("The given function is y=x^2.2-69 \n\n");
a=input("Enter first approximation : ");
b=input("Enter second approximation : ");
d=input("Enter accuracy : ");
printf('succesive iterations    \ta\t    b\t    f(a)\t    f(b)\t\  x1\n');
for i=1:25
    x1=b*f(a)/(f(a)-f(b))+a*f(b)/(f(b)-f(a));
    if(f(a)*f(x1))>0
        b=x1;
    else
        a=x1;
    end
    if abs(f(x1))<d
        break
    end
    printf('                         \t%f  %f  %f  %f  %f\n',a,b,f(a),f(b),x1);
end
printf('the root of the equation is  %f',x1);

Add False position method or Regular falsi method

Simpson's three by eight rule

Simpson's three by eight rule

Code is Here

clear;clc
fxn=input("Enter the fuction : (eg:y=(x^2+5*x+6)) : ")
deff('y=f(x)',fxn);
printf("The given function is %s\n\n",fxn);
a=input('Inter the lower limit : ')
b=input('Inter the upper limit : ')
n=input('Inter the value of n : ')
h=(b-a)/n
for i=0:n
    X(1,i+1)=a+h*i
    Y(1,i+1)=f(a+h*i)
end
printf("x=")
disp(X)
printf("y=")
disp(Y)
a1=Y(1,1)+Y(1,n+1);
a2=0
for j=3:3:n-1
    a2=a2+Y(1,j+1);
end
a3=0
for k=0:n-1
    p=modulo(k,3)
if p==0
else
    a3=a3+Y(1,k+1);
end
end
i=(3*h/8)*(a1+2*a2+3*a3);
printf("The value of Integral is : ")
disp(i)

Simpson's three by eight rule

ODE by Modified Euler's Method Scilab code

ODE by Modified Euler's Method Scilab code

Code is Here

ODE by Euler's Method Scilab code

ODE by Euler's Method Scilab code

Code is Here

clear
deff('z=f(x,y)','z=3*x+y/2');
printf("The given function is dy/dx=x+y\n");
X(1,1)=input('Enter the value of x0 : ')
Y(1,1)=input('Enter the value of y0 : ')
b=input('Enter the value of x : ')
n=input('Enter the value of n : ')
h=(b-X(1,1))/n
for i=2:n+1
    X(1,i)=X(1,i-1)+h
end
disp(X,"X=")
for j=2:n+1
    Y(1,j)=Y(1,j-1)+h*f(X(1,j-1),Y(1,j-1))
end
disp(Y,"y=")
printf("\nSo Value of y(%d) is = %f\n",n,Y(n+1))

ODE by Euler's Method Scilab code

Trapezoidal Method Scilab Code

Trapezoidal Method Scilab code

Code is Here

clear
fxn=input("Enter the fuction : (eg:y=(x^2+5*x+6)) : ")
deff('y=f(x)',fxn);
printf("The given function is %s\n\n",fxn);
a=input('Enter the lower limit : ')
b=input('Inter the upper limit : ')
n=input('Enter the value of n : ')
h=(b-a)/n
for i=0:n
    X(1,i+1)=a+h*i
    Y(1,i+1)=f(a+h*i)
end
printf ("x=")
disp (X)
printf ("y=")
disp (Y)
a1=Y(1,1)+Y(1,n+1);
a2=0
for j=2:n
    a2=a2+Y(1,j)
end
i=(h/2)*(a1+2*a2);
printf('The value of Integral is : ')
disp(i)

Trapezoidal Method Scilab Code

Simpson's one third (1/3) rule Scilab code

Simpson's one third (1/3) rule Scilab code

Code is Here

clear
fxn=input("Enter the fuction : (eg:y=(x^2+5*x+6)) : ")
deff('y=f(x)',fxn);
printf("The given function is %s\n\n",fxn);
a=input('Enter the lower limit : ')
b=input('Inter the upper limit : ')
n=input('Enter the value of n : ')
h=(b-a)/n
for i=0:n
    X(1,i+1)=a+h*i
    Y(1,i+1)=f(a+h*i)
end
printf ("x=")
disp (X)
printf ("y=")
disp (Y)
a1=Y(1,1)+Y(1,n+1);
a2=0
for j=2:2:n
    a2=a2+Y(1,j)
end
a3=0
for l=3:2:n-1
    a3=a3+Y(1,l)
end
i=(h/3)*(a1+4*a2+2*a3);
printf('The value of Integral is : ')
disp(i)

Simpson's one third (1/3) rule Scilab code

Bisection Method Scilab code

Bisection Method code Scilab

Code is Here

clc;clear
deff('y=f(x)','y=x^3-1');
x1=input("Enter first approximation: ");
x2=input("Enter second approximation : ");
d=input("Enter accuracy : ");
c=1;
printf('Succesive approximation: \t   x1\t   \tx2\t   \tm\t   \tf(m)\n');
while abs(x1-x2)>d
    m=(x1+x2)/2;
printf('                          \t%f\t%f\t%f\t%f\n',x1,x2,m,f(m));
    if f(m)*f(x1)>0
        x1=m;
    else
        x2=m; 
end
c=c+1;
end
printf('The solution of equation after %i iteration is %g',c,m);
//done

Bisection Method Scilab code

Secant Method Scilab Code

Code is Here

clc;clear
deff('y=f(x)','y=x^3-2*x-5');
x1=2,x2=3// initial values 
n=1; c=0; 
printf('successive iterations \tx1 \tx2\t x3\t f(x3)\n') 
while n==1 
    x3=(x1*f(x2)-x2*f(x1))/(f(x2)-f(x1)); 
    printf(' \t%f\t%f\t%f\t%f\n',x1,x2,x3,f(x3)); 
    if f(x3)*f(x1)>0
x2=x3;
else
x1=x3;
end
if abs(f(x3))<0.0001 then
break;
end
c=c+1;
end
printf('the root of the equation after %i iteration is: %f',c,x3 )

Secant Method Scilab Code

LU Decomposition Method Scilab code

Code is here

clear; // Remove clear, clc from code if you want to access existing stored variable from the memory
//LU decomposition method
clc;clear;close;
A=[2,3,1;1,2,3;3,1,2];
B=[9;6;8]
L(1,2)=0,L(1,3)=0,L(2,3)=0;
U(2,1)=0,U(3,1)=0,U(3,2)=0;
for i=1:3
L(i,i)=1;
end
for i=1:3
U(1,i)=A(1,i);
end
L(2,1)=1/U(1,1);
for i=2:3
U(2,i)=A(2,i)-U(1,i)L(2,1); end L(3,1)=A(3,1)/U(1,1); L(3,2)=(A(3,2)-U(1,2)L(3,1))/U(2,2);
U(3,3)=A(3,3)-U(1,3)L(3,1)-U(2,3)L(3,2);
printf(‘The Matrix A in Triangle form\n \n’)
printf(‘Matrix L\n’);
for i=1:3
for j=1:3
printf(‘%.2f ‘,L(i,j));
end
printf(‘\n’);
end
printf(‘\n \n’);
printf(‘Matrix U\n’);
for i=1:3
for j=1:3
printf(‘%.2f ‘,U(i,j));
end
printf(‘\n’);
end
Y=L^-1B; X=U^-1Y;
printf(‘ the values of x=%f,y=%f,z=%f’,X(1,1),X(2,1),X(3,1));

Fees structure of IIT colleges in India

Fees structure of IIT colleges in India

Details of the IITs B.Tech Fee Structure

Name of IITs	Category	Amount in Rs.	Total Fees
IIT Bombay	Academic Fee	1,22,300	Click Here
	Hostel and Hostel and Mess Charges	3,550
IIT Bhilai	Academic Fee	123500	Click Here
	Hostel and Hostel and Mess Charges	30500*
IIT Bhubaneshwar	Academic Fee	125568	Click Here
	Hostel and Hostel and Mess Charges	22,500
IIT Delhi	Academic Fee	1,16,450	Click Here
	Hostel and Mess Charges	8,000
IIT Dhanbad	Academic Fee	1,26,470	Click Here
	Hostel and Mess Charges	15,000
IIT Dharwad	Academic Fee	1,16,750	Click Here
	Hostel and Mess Charges	26,000
IIT Gandhinagar	Academic Fee	1,34,000	Click Here
	Hostel and Mess Charges	19,000
IIT Goa	Academic Fee	1,21,679	Click Here
	Hostel and Mess Charges	17,000
IIT Guwahati	Academic Fee	1,27,650	Click Here
	Hostel and Mess Charges	21,880
IIT Hyderabad	Academic Fee	1,24,675	Click Here
	Hostel and Mess Charges	28,275
IIT Indore	Academic Fee	1,26,000	Click Here
	Hostel and Mess Charges	16,000
IIT Jammu	Academic Fee	89,250	Click Here
	Hostel and Mess Charges	45,750
IIT Jodhpur	Academic Fee	1,25,400	Click Here
	Hostel and Mess Charges	7,000
IIT Kanpur	Academic Fee	1,13,500	Click Here
	Hostel and Mess Charges	23,400
IIT Kharagpur	Academic Fee	1,20,150	Click Here
	Hostel and Mess Charges	28,855
IIT Madras	Academic Fee	1,08,450	Click Here
	Hostel and Mess Charges	33,215
IIT Mandi	Academic Fee	1,66,500	Click Here
	Hostel and Mess Charges	18,500
IIT Palakkad	Academic Fee	1,13,750	Click Here
	Hostel and Mess Charges	27,100
IIT Patna	Academic Fee	1,19,250	Click Here
	Hostel and Mess Charges	5,000
IIT Roorkee	Academic Fee	1,16,250	Click Here
	Hostel and Mess Charges	30,250
IIT Ropar	Academic Fee	1,06,650	Click Here
	Hostel and Mess Charges	20,000
IIT Tirupati	Academic Fee	1,14,800	Click Here
	Hostel and Mess Charges	30,600
IIT Varanasi	Academic Fee	1,21,465	Click Here
	Hostel and Mess Charges	12,000