Friday, September 20, 2019

Bisection Method Scilab code

Bisection Method code Scilab



Code is Here



clc;clear
deff('y=f(x)','y=x^3-1');
x1=input("Enter first approximation: ");
x2=input("Enter second approximation : ");
d=input("Enter accuracy : ");
c=1;
printf('Succesive approximation: \t   x1\t   \tx2\t   \tm\t   \tf(m)\n');
while abs(x1-x2)>d
    m=(x1+x2)/2;
printf('                          \t%f\t%f\t%f\t%f\n',x1,x2,m,f(m));
    if f(m)*f(x1)>0
        x1=m;
    else
        x2=m; 
end
c=c+1;
end
printf('The solution of equation after %i iteration is %g',c,m);
//done


Bisection Method Scilab code
Bisection Method Scilab code


Secant Method Scilab Code

Secant Method Scilab Code


Code is Here



clc;clear
deff('y=f(x)','y=x^3-2*x-5');
x1=2,x2=3// initial values 
n=1; c=0; 
printf('successive iterations \tx1 \tx2\t x3\t f(x3)\n') 
while n==1 
    x3=(x1*f(x2)-x2*f(x1))/(f(x2)-f(x1)); 
    printf(' \t%f\t%f\t%f\t%f\n',x1,x2,x3,f(x3)); 
    if f(x3)*f(x1)>0
x2=x3;
else
x1=x3;
end
if abs(f(x3))<0.0001 then
break;
end
c=c+1;
end
printf('the root of the equation after %i iteration is: %f',c,x3 )


Secant Method Scilab Code
Secant Method Scilab Code

LU Decomposition Method Scilab code

LU Decomposition Method Scilab code


Code is here

clear; // Remove clear, clc from code if you want to access existing stored variable from the memory
//LU decomposition method
clc;clear;close;
A=[2,3,1;1,2,3;3,1,2];
B=[9;6;8]
L(1,2)=0,L(1,3)=0,L(2,3)=0;
U(2,1)=0,U(3,1)=0,U(3,2)=0;
for i=1:3
L(i,i)=1;
end
for i=1:3
U(1,i)=A(1,i);
end
L(2,1)=1/U(1,1);
for i=2:3
U(2,i)=A(2,i)-U(1,i)L(2,1); end L(3,1)=A(3,1)/U(1,1); L(3,2)=(A(3,2)-U(1,2)L(3,1))/U(2,2);
U(3,3)=A(3,3)-U(1,3)L(3,1)-U(2,3)L(3,2);
printf(‘The Matrix A in Triangle form\n \n’)
printf(‘Matrix L\n’);
for i=1:3
for j=1:3
printf(‘%.2f ‘,L(i,j));
end
printf(‘\n’);
end
printf(‘\n \n’);
printf(‘Matrix U\n’);
for i=1:3
for j=1:3
printf(‘%.2f ‘,U(i,j));
end
printf(‘\n’);
end
Y=L^-1B; X=U^-1Y;
printf(‘ the values of x=%f,y=%f,z=%f’,X(1,1),X(2,1),X(3,1));

Monday, September 16, 2019

Fees structure of IIT colleges in India

Fees structure of IIT colleges in India

Details of the IITs B.Tech Fee Structure
Name of IITs
Category
Amount in Rs.
Total Fees
Academic Fee
1,22,300
Hostel and Hostel and Mess Charges
3,550
Academic Fee
123500
Hostel and Hostel and Mess Charges
30500*
Academic Fee
125568
Hostel and Hostel and Mess Charges
22,500
Academic Fee
1,16,450
Hostel and Mess Charges
8,000
Academic Fee
1,26,470
Hostel and Mess Charges
15,000
Academic Fee
1,16,750
Hostel and Mess Charges
26,000
Academic Fee
1,34,000
Hostel and Mess Charges
19,000
Academic Fee
1,21,679
Hostel and Mess Charges
17,000
Academic Fee
1,27,650
Hostel and Mess Charges
21,880
Academic Fee
1,24,675
Hostel and Mess Charges
28,275
Academic Fee
1,26,000
Hostel and Mess Charges
16,000
Academic Fee
89,250
Hostel and Mess Charges
45,750
Academic Fee
1,25,400
Hostel and Mess Charges
7,000
Academic Fee
1,13,500
Hostel and Mess Charges
23,400
Academic Fee
1,20,150
Hostel and Mess Charges
28,855
Academic Fee
1,08,450
Hostel and Mess Charges
33,215
Academic Fee
1,66,500
Hostel and Mess Charges
18,500
Academic Fee
1,13,750
Hostel and Mess Charges
27,100
Academic Fee
1,19,250
Hostel and Mess Charges
5,000
Academic Fee
1,16,250
Hostel and Mess Charges
30,250
Academic Fee
1,06,650
Hostel and Mess Charges
20,000
Academic Fee
1,14,800
Hostel and Mess Charges
30,600
Academic Fee
1,21,465
Hostel and Mess Charges
12,000